Greatest Animated Movie Sidekicks of All Time
Dory (Finding Nemo) or Olaf (Frozen)
Pick Your Favorite
VS
Your GOAT List
Why This Battle Matters
Who really holds our hearts in the icy depths of the ocean and the snowy folds of Arendelle? Dory, with her forgetful charm and unwavering loyalty, navigates the vast and often confusing seas, while Olaf, the ever-optimistic snowman, dreams of warm hugs in the frosty air. This isn't just about which sidekick makes us laugh more—it's a cultural showdown, pitting the aquatic against the arctic, spontaneity against innocence. As fans, you shape the legacy: Will it be the one who reminds us to 'just keep swimming' or the one who believes in the sun on a cloudy day? Choose who truly warms the spirit of animated adventures.
🔥 Fan Takes
How Fans Are Voting
In this battle:
Fans currently prefer Olaf (Frozen) over Dory (Finding Nemo) when it comes to the greatest Animated Movie Sidekicks of all time. In head-to-head matchups, fans pick Olaf (Frozen) 63.6% of the time over Dory (Finding Nemo).
Across all battles:
Olaf (Frozen) win rate: 55.6%
Dory (Finding Nemo) win rate: 51.6%
Fan FAQs
Why is Olaf winning by so much against Dory in the Greatest Animated Movie Sidekicks league?
Olaf's larger lead can be chalked up to his unwavering positivity and the way he embodies the spirit of joy and innocence in 'Frozen'. His ability to deliver laughter and light in chilly situations makes him a standout favorite in this matchup.
Why do fans adore Dory from 'Finding Nemo'?
Dory wins hearts with her unforgettable line, 'Just keep swimming!' Fans love her optimistic attitude and short-term memory loss quirks that add both humor and depth to her character. She teaches us all about perseverance and friendship in the most endearing way.
Who is better: Dory or Olaf?
Right now, Olaf is leading in the votes over Dory. Fans seem to resonate with his humorous, carefree spirit and his knack for lightening up any frosty situation. It’s that charm and comic relief he brings to 'Frozen' that's giving him the edge.